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SSC MTS Numerical Ability Set – 2

1. The value of (0.03)2 – (0.01)2 / 0.03 – 0.01  is

(1) 0.02

(2) 0.004

(3) 0.4

(4) 0.04

Show Answer

Answer : (4) 0.004


Explanation :


(4) (0.03)2 -(0.01)2 /  0.03 – 0.01


[Using a2 – b2 = (a + b) (a – b)]


= (0.03 + 0.01)(0.03 – 0.01) / 0.03 – 0.01


= 0.03 + 0.01 = 0.04


2. The H.C.F of two numbers is 8. Which one of the following can never their LC.M?

(1) 24

(2) 48

(3) 56

(4) 60

Show Answer

Answer : (4) 60


Explanation :


(4) HCF of two numbers is 8. This means 8 is a factor common to both the numbers. LCM is common multiple for the two numbers. It is divisible by the two numbers. So, the requird answer = 60


3. A B and C rent  a pasture. A puts in 10 oxen for 7 months. B 12 oxen for 5 months and C 15 oxen fro 3 months for grazing. If the rent of the pasture is Rs. 175 /. how much must C pay as his share of rent?

(1) Rs 45/-

(2) Rs 50/-

(3) Rs 55/-

(4) Rs 60/-

Show Answer

Answer : (1)  Rs 45/-


Explanation :


(1) Share of rent = (number of oxen x time)


A : B : C


= (10 * 7) : (12 * 5) : (15 * 30)


A : B : C = 70 : 60 : 45


A : B : C = 14 : 12 : 9


C’s share of rent = 9 / 14 + 12 + 9 * 175


= 9 / 35 * 175 = 45


Therefore C’s share of rent is Rs. 45


4. A reduction of 20% in the price of oranges enables a man to buy 5 oranges more for Rs. 10 / -. The price of an orange before reduction was :

(1) 20 paise

(2) 40 paise

(3) 50 paise

(4) 60 paise

Show Answer

Answer : (3) 50 paise


Explanation :


(3) 20% of Rs. 10


= 20 / 100 * Rs. 10 = Rs. 2


Reduced price of 5 oranges = Rs. 2


Therefore Reduced price of 1 orange


= Rs. 2 / 5 = 200 / 5 paise = 40 paise


Original price of 1 orange 


= 40 / 1 – 0.20 = 40 / 0.8 = 400 / 8 = 50 paise


5. In an examination, a student who gets 20% of the maximum marks fails by 5 marks. Another student who scores 30% of the maximum marks gets 20 marks more than the pass marks. The necessary percenatge required for passing is:

(1) 32%

(2) 23%

(3) 22%

(4) 20%

Show Answer

Answer : (3) 22%


Explanation :


(3) Let the maximum marks be x.


According to question.


20% of x + 5 = 30% of 


x – 20


= (30 – 20)% of x = 25


= x = 25 * 100 / 10 = 250


Therefore Pass marks


= 20% of 250 + 5 = 55


Therefore percentage Pass marks


= 55 / 250 * 100 = 22%


6. When 60 is subtracted from 60% of a number, the result is 60. The number is :

(1) 120

(2) 150

(3) 180

(4) 200

Show Answer

Answer : (2) 150


Explanation :


(2) Let the number be x. Then x – 60% of x = 60


= x – 0.60x = 60 = 0.4x = 60


= x = 60 / 0.4 = x = 600 / 4


x = 150


Therfore The number is 150.


7. If 3 men of 6 women can do a piece of work in 16 daays, in how many days can 12 men and 8 women do the same piece of work?

(1) 4 days

(2) 5 days

(3) 3 days

(4) 2 days

Show Answer

Answer : (3) 3 days


Explanation :


(3) 3m = gw


Therefore m = 2w


12m + 8w = (12 * 2w) + 8w = 32w


Therefore 6 women can do the work in 16 days.


Therefore 32 women can do the work in


16 * 6 / 32 = 3 days


8. On what sum does the difference between the compound interest and the simple interest for 3 years at 10% id Rs. 31?

(1) Rs. 1500

(2) Rs. 1200

(3) Rs. 1100

(4) Rs. 1000

Show Answer

Answer : (4) Rs. 1000


Explanation :


(4) Let the sum be Rs. x


r = 10%, n = 3 years


S.I. = x * r * n / 100


S.I = x * 10 * 3 / 100 = 3 / 10 x


C.I. = [(1 + R / 100)N – 1]x


= [(1 + 10 / 100)3 – 1]x = [(11 / 10)3 – 1]x


= (1331 / 1000 – 1)x = 331 / 1000 x


331 / 1000 x – 3 / 10x = 31


or, (331 – 300) / 1000 x = 31


or, 31 / 1000 x = 31 or, x = 1000


Therefore Sum = Rs. 1000


9. At what percent per annum will Rs. 3000 amount to Rs. 3993 in 3 years if the interest is compounded annually?

(1) 9%

(2) 10%

(3) 11%

(4) 13%

Show Answer

Answer : (2) 10%


Explanation :


(2) P = Rs. 3000, A = Rs. 3993, 


n = 3 years


A = P [1 + r / 100]n


Therefore [1 + r / 100]n = A / P


[1 +r / 100]3 = 3993 / 3000 = 1331 / 1000


[1 + r / 100]3 = [11 / 10]3


= 1 + r / 100 = 11 / 10 = r / 100 = 11 / 10 – 1


= r / 100 = 1 / 10 = r = 100 / 10


r = 10%


10. Given that  0.111 …. = 1 / 9; 0.444

is equal to :

(1) 1 / 90

(2) 2 / 45

(3) 1 / 99

(4) 4 / 9

Show Answer

Answer : (4) 4 / 9


Explanation :


(4) Given : 0.111…. = 1 / 9


0.444….. = 4 * 0.1111….


= 4 * 1 / 9 = 4 / 9


 

 

 

 

 

 

 

 

 

 

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